0000 0001 2.2 0003 C:\SCIWKSHP\ROTATE.SWS 0002 0 FFFF 0100 0101 0 0102 148 0121 Smart Pulley (Linear) 0122 0 0123 0.015000 FFFF 1000 1002 100000 1003 1 0611 0 FFFF 0200 777 0201 4 0202 20 0203 627 0204 406 0209 -1 020A -1 020B -4 020C -4 0205 1 0206 0 0208 1 FFFF 0200 850 0201 7 0202 27 0203 113 0204 213 0209 -1 020A -1 020B 0 020C 0 0205 1 0206 0 0208 1 0303 0 0304 0 0305 0.000000 030A 1 0306 0 0307 0 0308 0.000000 030B 1 FFFF 0900 570 0901 Velocity vs. Time 0902 133 0903 24 0904 474 0905 283 0915 21 0916 370 0917 -4 0918 -4 0906 1 0913 0 0914 1 0907 0 090D 1 0908 0 090C v 09FF 0F01 0 0F02 1 0F03 1 0F04 1 0F05 0 0F06 0 0F07 0.000000 0F08 0 0F09 0 0F0A 0.000000 0F0B 0 0F0C 1 0F0D 0.000000 0F0E 6.276300 0F16 1 0F17 1 0F18 1 0F19 0 0F41 0 0F42 1.219962 0F43 9.163742 0F44 0.000000 0F45 0.000000 0F46 0.000000 0F47 0.000000 0F4E 0 0F49 0 0F52 0 0F4A 0 0F4B 100 0F4F 1 0F53 2 0F4C 0 FFFF 0200 820 0201 217 0202 22 0203 416 0204 383 0209 -1 020A -1 020B -1 020C -1 0205 0 0206 0 0208 0 0501 2487 0502 Experiment P26: Rotational Inertia (Smart Pulley) PURPOSE The purpose of this laboratory activity is to measure the rotational inertia of a ring experimentally and to compare this value to the theoretical value. THEORY Theoretically, the rotational inertia, I, of a ring is given by I = 1/2 M ( R1 2 + R2 2 ) Equation 1 where M is the mass of the ring, R1 is the inner radius of the ring, and R2 is the outer radius of the ring. To find the rotational inertia of the ring experimentally, a known torque is applied to the ring and the resulting angular acceleration is measured. Since t = Ia I = t / a Equation 2 where a is the angular acceleration and t is the torque. Now, t = r x F Equation 3 where r is the distance from the center of the ring to the point where a force is applied, and F is the applied force. The value of r x F is r F sin theta where theta is the angle between r and the direction of F, the applied force. The torque is maximum when r and F are perpendicular. In this case, the applied force is the tension (T) in a string that is tied to a step pulley that is part of a rotational apparatus. The string is pulled by a hanging mass m. The value of r is the radius of the step pulley on the apparatus. The radius is perpendicular to the applied force (Tension). Therefore, the torque is: t = r T Equation 4 Applying Newton's Second Law for the hanging mass, m, results in: SUM F = m a = mg - T Solving for the tension in the string gives T = m ( g -a ) The torque is: t = r T = r m ( g - a ) Equation 5 The linear acceleration a of the hanging mass is the tangential acceleration, aT, of the rotating apparatus. The angular acceleration is related to the tangential acceleration as follows: a = at / r Equation 6 Substituting Equation 5 and Equation 6 into Equation 2 gives: I = t / a = r m ( g - a ) / ( at / r ) = r m ( g - a ) r / at = mgr2 / at - mr2 = mr2 ( g / at - 1 ) The rotational inertia, I, can be calculated from the tangential acceleration, aT. PROCEDURE For this activity, the Smart Pulley measures the motion of a hanging mass that is connected by a string to a step pulley on the rotational apparatus. The Science Workshop program calculates and displays velocity versus time. The slope of the best fit line of velocity versus time is the value of acceleration. Please refer to the lab manual for a detailed procedure. Science - Stretching the Boundaries (Science Workshop 2.2) 0503 1 0504 0 0505 0 FFFF 0200 900 0201 20 0202 40 0203 282 0204 180 0209 -1 020A -1 020B -1 020C -1 0205 0 0206 0 0208 0 FFFF 0200 800 0201 200 0202 75 0203 290 0204 110 0209 -1 020A -1 020B -1 020C -1 0205 0 0206 0 0208 0 0401 1 0402 255 0403 1000.000000 0404 0.000000 0405 0 FFFF FFFF